If xx = a cosec θa cosec θ and yy = b sec θb sec θ, prove that (a2x2+b2y2)(a2x2+b2y2) = 1.
Answer:
1
- We are told that [Math Processing Error] Also, [Math Processing Error]
- On squaring and adding (i) and (ii), we get (a2x2+b2y2)=sin2 θ+cos2 θ=1